Calculate the number of Al3+ atoms in 0.056g of Al2O3?

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Calculate the number of Al3+ atoms in 0.056g of Al2O3?

PLEASE HELP ME! I need some help for my assignment over here :)

2007-06-30 20:29:34 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

PLZ tell me HOW to get the answer, the real logic..... behind it....

2007-06-30 20:38:19 · update #1

2 answers

Molar mass Al2O3 = 102 g / Mol
Moles Al2O3 = 0.056 / 102 = 0.000549
Moles Al3+ = 0.000549 x 2 = 0.00110
Number of Al3+ ions = 0.00110 x 6.02 x10^23 = 6.6 x 10^20

2007-06-30 23:00:42 · answer #1 · answered by Dr.A 7 · 0⤊ 0⤋

Molar mass of Al2O3 = 102 g

No. of Al3+ atoms = 2 * 0.056/102

2007-07-01 03:35:36 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 1⤋