2007-06-30 15:43:37 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
150g..C6H23O Mol. mass = (12 x 6) + 23 + 32 = 127
42.7g..KI Mol. mass = 39 +127 = 166
320g..FeCl2 Mol. mass = 56 + 71 = 127
50g..H2O Mol. mass = 18
The number of moles of each component :-
= Mass/Mol. mass.
C6H23O = 150 ÷ 127 = 1.18
KI = 42.7 ÷ 166 = 0.26
FeCl2 = 320 ÷ 127 = 2.52
H2O = 50 ÷ 18 = 2.78
Total moles = 1.18 + 0.26 + 2.52 + 2.78 = 6.74 moles.
The Mol. fraction of FeCl2 = 2.52 ÷ 6.74 = 0.374. (37.4%)
2007-06-30 16:37:30 · answer #1 · answered by Norrie 7 · 0⤊ 0⤋
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2016-05-17 12:53:08 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Convert each item to moles using the respective molecular mass.
Total up the moles of all the items. The mole fraction of FeCl2 is then a simple ratio of the moles of FeCl2 to the grand total of moles.
2007-06-30 15:47:09 · answer #3 · answered by reb1240 7 · 0⤊ 0⤋