can someone explain how to graph 3x + 2y =6?

Answer 1

This is the equation of a straight line, so you need TWO points

if x=0, y=3
if y=0, x = 3

Draw the two points in graph paper, connect them and you are done!

Answer 2

This is very easy for you to do, I will walk you through it.

First solve for y.

By doing this you bring 3x to the other side and get:

2y = 6 - 3x

Now to get the y by itself you want to divide by two so you get:

y = (6/2) - (3x/2) which simplifies to y = 3 - (3x/2)

Now to graph it you plug in values for x and get a value for y. The value that you put it as your x is the value you move on the x axis and the value you get out for y is the value you move up on the y axis.

For example:

x = 0

So y = 3 - (3*0 / 2)
y = 3
So your first point is (0, 3)

x = 1

So y = 3 - (3*1 / 2)
y = 3 - (3/2)
y = 3/2
So your next point would be (1, 3/2)

You can do this for as many values as you want! Hope this helps. The way the guy above did it is also right since it is a straight line. The problem with his method of showing you is that if you have an x^2 then it is a curved line and you can't just draw two points, you have to drawn many. Good luck.

Answer 3

rearrange this to the familiar eqution:

y = mx + b

2y = -3x + 6

y = - 1.5 x + 3

this is a linear graph (i.e it is a line )
so, you need two points to draw a line.
first point: set x = 0, y = 3
2nd point: set y = 0, x = 2

now you have 2 points: (0,3) and (2, 0)
graph these 2 points on graph paper
then draw a line through these 2 points

Answer 4

You need to solve for y (if you're doing this they way I learned to)

3x + 2y = 6

2y = -3x + 6

y = - 3/2x + 3

-3/2 is your slope and 3 is your y intercept.

Now make a value table for x and y

Pick some random numbers for x (like -2,-1,0,1,2) and plug them in and solve for y for each one. This gives you a table of ordered pairs. The value for y for each x is your ordered pair. Then just graph the ordered pairs

Answer 5

an easy way is to enter values for x and y that make the statement true.

ex. 3(-2) + 2 (6)= 6
-6 + 12 = 6

So (-2,6) is one of your points. Keep creating points until you determine the curve of the graph

Answer 6

pick a couple of x values (say -2, -1, 0, 1 and 2) plug them in for x... so you get some y values associated with that x. Then you have points you can graph, like (0,3).

Answer 7

3x + 2y = 6
3x = 6 - 2y
x = (6 - 2y) / 3
x = 2 - 2/3y

3(2 - 2/3y) + 2y = 6
6 - 2y + 2y = 6
- 2y + 2y = 6 - 6
0 = 0

There is no solution.

Answer 8

3x+2y=6
x=0,y=3
y=0,x=2
this straight line passes through ()0,3 and(2,0) mark these points and join them. this is the reqd. graph.