2007-06-30 08:34:06 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
100b^2 - 144a^4
= (10b+12a^2)(10b-12a^2)
2007-06-30 08:38:15 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
100b^2-144a^4 = difference of squares
(10b - 12a^2)(10b + 12a^2) = factor out common terms
4(5b - 6a^2)(5b+6a^2)
2007-06-30 15:44:03 · answer #2 · answered by Poetland 6 · 0⤊ 0⤋
basic formula
x^2 - y^2 = (x+y) * (x-y)
100b^2 - 144a^4 =
= (10b)^2 - (12a^2)^2
= (10b + 12a^2) * (10b - 12a2)
= 4 * (5b + 6a^2) * (5b - 6a^1)
where
x = 10b
y = 12a^2
2007-06-30 16:01:03 · answer #3 · answered by buoisang 4 · 0⤊ 0⤋
100 b^2 - 144 a^4 = (10 b)^2 - (12 a^2)^2
= (10 b - 12 a^2) (10 b + 12 a^2)
2007-06-30 15:39:07 · answer #4 · answered by Sam 3 · 0⤊ 0⤋
4(5b - 6a^2)(5b + 6a^2).
All the answers (so far) show a factor.
2007-06-30 15:44:01 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(10b-12a^2)(10b+12a^2)
2007-06-30 16:02:29 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(10b+12a^2)(10b-12a^2)
4(5b+6a^2)(5b-6a^2)
4(5b+6a^2){(5b)^1/2+6^1/2.a}{(5b)^1/2-6^1/2.a}
2007-06-30 16:09:16 · answer #7 · answered by MAHAANIM07 4 · 0⤊ 0⤋