2007-06-30 07:43:02 · 7 answers · asked by randall_gilmore 1 in Science & Mathematics ➔ Mathematics
Factor them in pairs
3x^2 (x + 3) + (x+3)
= (x+3)*(3x^2 + 1)
2007-06-30 07:49:46 · answer #1 · answered by Dr D 7 · 1⤊ 0⤋
3x^3 + 9x^2 + x + 3 factored is (x+3)*((3*x^2)+1)
2007-06-30 07:50:19 · answer #2 · answered by ? 5 · 0⤊ 0⤋
3x^3 + 9x^2 + x + 3 = 3x^2 (x + 3) + (x + 3)
= (3x^2 + 1) (x + 3)
2007-06-30 07:49:20 · answer #3 · answered by Sam 3 · 0⤊ 0⤋
3x²(x+3)+x+3= (x+3)(3x²+1)
2007-06-30 07:51:49 · answer #4 · answered by anton p 4 · 0⤊ 0⤋
(3x^2+1) (x+3)
2007-06-30 07:48:09 · answer #5 · answered by Anonymous · 0⤊ 0⤋
3x^3+9x^2+x+3
3x^2(x+3)+1(x+3)
(3x^2+1)(X+3)
2007-06-30 07:54:48 · answer #6 · answered by MAHAANIM07 4 · 0⤊ 0⤋
Using synthetic division:-
**- 3|3****9****1****3
*****|**** -9****0***-3
----------------------------
*****3****0*****1****0
---------------------------
gives:-
(x + 3) as a factor with other factor being
(3x² + 1)
(x + 3).(3x² + 1) is answer upon factorising.
2007-07-03 20:57:07 · answer #7 · answered by Como 7 · 0⤊ 0⤋