2007-06-30 06:33:12 · 7 answers · asked by randall_gilmore 1 in Science & Mathematics ➔ Mathematics
well theyve both got 7 in common so id have the 7 outside the bracket then you can just input what you need to get those multiples of 7 into the bracket so:
7(2x^2 + 5x)
then you see x common to both
so you can take one x out the bracket giving you
7x(2x+5)
2007-06-30 06:45:10 · answer #1 · answered by Anonymous · 0⤊ 0⤋
14x^2 + 35x = 7x (2x + 5)
2007-06-30 13:37:18 · answer #2 · answered by Sam 3 · 0⤊ 0⤋
14x^2 + 35x = 7x(2x+5)
2007-06-30 13:37:12 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
Factor out a 7x then you get
7x(2x+5)
2007-06-30 13:38:22 · answer #4 · answered by Rocketman 6 · 0⤊ 0⤋
14x^2+35x
7x(2x+5)
2007-06-30 15:28:16 · answer #5 · answered by MAHAANIM07 4 · 0⤊ 0⤋
          factor out 7x
          7x (2x + 5)
2007-06-30 13:40:28 · answer #6 · answered by 7 · 0⤊ 0⤋
= 7x.(2x + 5)
2007-07-04 02:47:56 · answer #7 · answered by Como 7 · 0⤊ 0⤋