maximum kinetic energy of the ejected electrons?

5 ⤊

maximum kinetic energy of the ejected electrons?

A monochromatic light beam with a quantum energy value of 3.0 eV is incident upon a photocell. The work function of the photocell is 1.6 eV. What is the maximum kinetic energy of the ejected electrons?

2007-06-29 22:43:32 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics

3 answers

3.0 eV - 1.6 eV = 1.4 eV

2007-06-29 23:17:58 · answer #1 · answered by Helmut 7 · 4⤊ 0⤋

As u may know we have all of the foton energy will be divided in 2 part one for work function and the other for kinetic energy so K=3.0-1.6=2.4 = eV (this V is the voltage which with more than that no current will be seen)

2007-06-29 23:12:02 · answer #2 · answered by FifiLone 2 · 1⤊ 3⤋

E=hv+1/2mv^2
E=3.0*1.6*10^-19
hv=1.6*1.6*10^-19
1/2mv^2=subtract the two.
IIT special.

2007-06-30 19:49:19 · answer #3 · answered by Vikas 3 · 0⤊ 0⤋