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the plane y + z =3 intersects the cylinder x^2 + y^2 = 5 in an ellipse. Find the parametric equations for the tangent line to this ellipse at the point (1,2,1)
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Well i believe i let x = cost and y=sint and z=3-sint but then do i take the derrivate of each and then just plug in the point? it seems to straight forward. please help.

2007-06-29 19:01:29 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

The parametric equations of the cylinder are x = √5*cost, y = √5 * sint. (The equation x^2 + y^2 = r^2 is a circle with radius r, and its parametric equations are x = r*cost, y = r*sint.)

Your ellipse equations should then be

x = √5*cost, y = √5*sint , z = 3 - √5*sint

You just need the parametric equations of a line;

x = a*t + b, y = c*t + d, z = e*t + f

Find the value of t0 from your ellipse parametric formulas that gives the point (1,2,1): x = 1, y = 2, z = 1. Then take the derivative of the each of the ellipse equations (w.r.t. t), evaluate it at t0 to get the values of a, c, and e;

Plug that value of t0 into the new line equations, find the values of b, d and f to make x = 1, y = 2, z = 1)

2007-06-30 07:21:50 · answer #1 · answered by gp4rts 7 · 0 1

It's all a conspiracy!

2007-06-29 19:52:58 · answer #2 · answered by βread⊆ℜumbs™ 5 · 0 2

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