please..i really need help...thanks!
2007-06-29 18:51:51 · 3 answers · asked by Sofia 1 in Science & Mathematics ➔ Chemistry
Sorry! KMn4 should be KMnO4
2007-06-29 19:28:44 · update #1
2KMnO4 + 3H2SO4 <==> K2SO4 + 2MnSO4 + 3H2O + 5[O]
now as u add more MnSO4 , the concentration of the product will increase causing the eq. to shift at the left. [refer Le chatelier's principle] . More of the product will recombine to produce the reactants.So. in other words, yield of the products will decrease.
2007-06-29 22:12:37 · answer #1 · answered by s0u1 reaver 5 · 0⤊ 1⤋
Perhaps you are trying to oxidise oxalic acid using acidified KMnO4. The MnSO4 is then a catalyst for the reaction, because the Mn2+ ion catalyses this reaction. It is said to be autocatalytic.
Look up http://jchemed.chem.wisc.edu/JCESoft/CCA/CCA3/MAIN/AUTOCAT/PAGE1.HTM
2007-06-30 06:09:33 · answer #2 · answered by Gervald F 7 · 1⤊ 0⤋
u can substitute KMnO4 + H2SO4 as O.
2KMnO4(aq) + 3H2SO4(aq) â 2MnSO4(aq) + K2SO4(aq) + 3H2O(l) + 5O(g)
Ignore the other compounds, just look at the end of the reaction. 5 Oxygen atom are formed!!
so:
MnSO4 + O -->MnO2 + SO3
2007-06-30 04:28:40 · answer #3 · answered by Papilio paris 5 · 0⤊ 2⤋