Solve: 4^(x + 2) = 200
2007-06-29 16:11:55 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
4^(x + 2) = 200
(x + 2)lg 4 = lg 200
x = (lg 200/lg 4) - 2
x = 1.821928095...
2007-06-29 16:16:36 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I believe the answer is 48 is for x. 48+2=50
4 raised to the 50th power is 200.
2007-06-29 23:18:44 · answer #2 · answered by Anonymous · 0⤊ 2⤋
4^(x+2) = 200
x+2 = log 200 / log 4
x + 2 = 3.821928
x = 1.821928
2007-06-29 23:20:04 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
(4^X)(4^2) = 200
(2^(2X))(2^4) = 200 = (2)(100)
2^(2X+3) = 100
LOG2 (2X + 3) = 2
LOG2 = 0.3
0.3(2X + 3) = 2
2X + 3 = 2 / 0.3
2X + 3 = 6.6
2X = 3.6
X = 1.8
I didn't need a calculator this way
2007-06-30 00:16:02 · answer #4 · answered by spirit dummy 5 · 0⤊ 0⤋