Find the equation of the axis of symmetry of the function y=2x^2-7x+5.?

Answer 1

This is an upward-facing parabola which can be rewritten as

y = 2x^2 - 7x + 5
= 2(x - 7/4)^2 + 5 - 49/8.

So it has a minimum at x = 7/4, and this is its axis of symmetry.

Answer 2

y = 2.[ x² - (7 / 2).x + 5/2 ]
y = 2.[(x² - (7 / 2).x + 49 /16) - 49 /16 + 5 /2 ]
y = 2.[ (x - 7 /4)² - 49 /16 + 40 /16 ]
y = 2.[ (x - 7 /4)² - 9 /16 ]
Axis of symmetry is x = 7 / 4