4x^3-12x^2-9x+27
i recieved 2 answers that factors correctly. but which one is COMPLETELY factored? or are they both completely factored? the answers were:
(4x^2-9)(x-3) and
(2x+3)(2x-3)(x-3)
if u are just guessing, plz do not answer this question. im confused enough already.
2007-06-29 13:52:26 · 4 answers · asked by ahhhh? 1 in Science & Mathematics ➔ Mathematics
The latter.
(4x²-9)=(2x+3)(2x-3)
2007-06-29 13:56:59 · answer #1 · answered by jsoos 3 · 0⤊ 0⤋
the second one (2x+3)(2x-3)(x-3) is factored completely, ie. it CANNOT be broken down any further.
Make sure it works. Multiply it out
(2x+3)(2x-3)(x-3) becomes....
(4x^2 - 9)(x - 3) becomes....
4x^3 - 9x + 27 - 12x^2 (which is what you started with!)
2007-06-29 20:59:51 · answer #2 · answered by theanswerman 3 · 0⤊ 0⤋
(2x+3)(2x-3)(x-3)
is totally factored~
(4x^2-9)= (2x+3)(2x-3)
therefore
4x^3-12x^2-9x+27=(2x+3)(2x-3)(x-3)
2007-06-29 20:57:32 · answer #3 · answered by blahman 2 · 0⤊ 0⤋
Both answers are correct, the second one is complete.
2007-06-29 20:58:24 · answer #4 · answered by Robert S 7 · 0⤊ 0⤋