a simplifying radicals problem?

Question

The directions are: simplify the following.
the square root of 5 TIMES the square root of 10 MINUS 2times the square root of 18

so the square root of 5 is one 'thing', the square root of 10 would be another 'thing' and 2 times the square root of 18 would be another 'thing'.
plz show show

Answer 1

sqrt(5) * sqrt(10) - 2sqrt(18)
= sqrt(5 * 10) - 2sqrt(2*9)
= sqrt(25*2) - 2*sqrt(2)*3
= 5*sqrt(2) - 6sqrt(2)
= - sqrt(2)

I hope this helps!

Answer 2

square root 5 * square root 10 - 2(squaree root 18)

so:

square root 5 * (square root 2 * square root 5) - (square root 2 x square root 9)

multiplying:

square root 10 * square root 25 - 3(square root 2)

5(square root 10) - 3 (square root 2)

5( square root 2 * square root 5) - 3 (square root 2)

common factor
(5 square root 5 - 3) square root 2

I did it way too long, but I think it's clear

Answer 3

sqrt 5 x sqrt 10 - 2 sqrt 18

sqrt 10 = sqrt (5x2)
= sqrt 5 x sqrt 2

sqrt18 = sqrt (9x2)
= 3 sqrt 2

2 sqrt18 = 6 sqrt 2

sqrt 5 x sqrt 5 x sqrt2 - 6 x sqrt 2
=5 sqrt 2 - 6 sqrt 2
= - sqrt2

Answer 4

sqrt(5)*sqrt(10)- 2sqrt(18)
=sqrt(50) -6sqrt(2)
=5sqrt(2)-6sqrt(2)
= -sqrt(2)

The above guys forgot the MINUS.

Answer 5

(sqrt5 x sqrt10) - (2x(sqrt18))
hope you know, how to take numbers out of the sqrt sign
= sqrt50 - (2x (3sqrt2))
= 5(sqrt2) - 6(sqrt2)
now that they have the same number in the sqrt sign.. you can subtract them as follows
= -1(sqrt2).........ANS

Answer 6

sqrt5*sqrt10*2sqrt18
sqrt50*2(3sqrt2)
sqrt50*6sqrt2
6(sqrt100)
6(10)
The answer is 10.

Answer 7

NOICE