a boat travels @63km/h.a cutter travels 24 Min's later @75km/h.find times each has travelled when cutter?

Question

a math question

Answer 1

Assuming you want to know how much time it will take for the cutter to reach the boat, we use the distance formula:
d = rt
For the first boat:
d = 63t
For the second boat, the distance d will be the same (the cutter reaches the first boat), and the time will be t - 24/60, 24 minutes less than the first boat.
d = 75(t - 24/60)
Since the distance, d is the same for each equation, we may set the right hand side of each equal to one another.
63t = 75(t - 24/60)
Simplifying on the right:
63t = 75t - 30
Solving for t:
-12t = -30
t = 2.5
So the first boat has been in the water 2.5hrs, or 2hr 30min,
and the second (faster) boat has been in the water for 2hr 6min when they meet.

Answer 2

I assume that you want to know how long until the cutter catches up with the boat.

The boat got a 24 minute head start.
24 min * 1 hr/60 min = 2/5 of an hour

Using distance = rate*time, at 63 km/h, the boat would have traveled 25.2 km in this time. So that is how big of a head start the boat got.

Now the cutter goes 12 km/h FASTER than the boat. So how long will it take to make up the 25.2 km deficit?
25.2 = 12 * t
25.2/12 = t
2.1 = t
So it takes it 2.1 hours, or 2 hours 6 minutes.

Thus the boat has been traveling for 2 hours 30 minutes and the cutter has traveled for 2 hours 6 minutes when the cutter catches up to the boat.

I hope this helps!

Answer 3

In order to fully solve for time, you would need to find the rate at which the boats moved per hour. To do this, simply substitute 60 in for H and divide the numerator by the denominator. Once you have done this, you should have an answer of 1.05 for the rate at which the boat traveled and an answer of 1.25 for the cutter. Once you have the rate of the boat figured out, move the decimal place of the 1.25 over 2 places to get 12. Then, divide the distance of the second boat 25.2 divided by 12 to get an answer of 2.1.

Answer 4

assume you meant find the time the cutter catches the boat

let t be the time the boat leaves, 24 minnutes later .4hr later, the cutter leaves. t - .4 is the time the cutter leaves

distance of the boat
x = 63t

distance of the cutter
x = 75(t - .4)

when the cutter catches the boat, their distance are equal

63t = 75(t - .4)
63t = 75t - 30
-12t = 30
t = 2.5hr

it takes the cutter 2.5 - .4 = 2.1hr hr to catch the boat.

Answer 5

Why don't you try an English lesson next time?