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For f(x) = x8 /9 -x17 /9 find the critical numbers.


Solution:
Since f¢(x)= ---------- we see that f¢(x)=0 if x= ------- and that f¢( --------) does not exist.

Therefore, the critical numbers are --------- and ----------

2007-06-29 11:40:51 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

To find critical vlues you differentiate the functionf first...
In this case after differentiating gives a whole number
i.e., 8/9 - 17/9 = -1.

then use f'(x) = 0 to get the answer...

here, -1 = 0.... which is absurd...
just make sure your question is correct...

2007-06-29 11:58:56 · answer #1 · answered by Sindhoor 2 · 0 0

I assume f¢(x) = the derivative of f(x). Peculiar notation!
Since f¢(x) = x^9 - 2x^18 we see that f¢(x)=0 if x= 0 or (1/2)^1/9 and that f¢( --------) does not exist.

Therefore, the critical numbers are 0 and (1/2)^1/9 .

2007-06-29 12:29:49 · answer #2 · answered by ironduke8159 7 · 0 0

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