dy/dx of y = (sin x)^2 sin x?

Question

need to find derivative of above problem. Thank you for your help.

Answer 1

y = (sinx)^3
dy/dx = 3*(sinx)^2 * cosx

You could rewrite this in various ways.

Answer 2

y = (sin ² x).sin x
y = (sin x) ³
dy/dx = 3.(sin x) ².cos x
dy/dx = 3.sin ² x.cos x

Answer 3

I like using the product rule, just to be different .
y'=sinx^2cosx+sinx(2sinx)(cosx)
y'=sinx^2cosx+2sinx^2cosx
y'=3sinx^2cosx.