2007-06-29 09:42:13 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2b
2007-06-29 09:50:03 · answer #1 · answered by giants fan jessica 4 · 0⤊ 0⤋
36ab^2 - 28ab
taking 4ab as common
4ab (9b-7)
2007-06-30 00:02:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Assume question is :-
36ab² - 28ab
= 4ab.(9b - 7)
2007-07-03 03:55:48 · answer #3 · answered by Como 7 · 0⤊ 0⤋
36ab^2 – 28ab
GCD of 36 and 28 is 4, GCD of b^2 and b is b
So GCD of above term is 4ab, taking common out side the bracket.
4ab(9b – 7)
2007-06-30 02:31:16 · answer #4 · answered by Pranil 7 · 0⤊ 0⤋
36ab² - 28ab
=4ab(9b-7)
2007-06-29 17:42:27 · answer #5 · answered by CrazyCoder 3 · 0⤊ 0⤋
36ab^2 - 28ab
factor out 4ab (GCF)
4ab(9b-7)
2007-06-29 16:54:57 · answer #6 · answered by Carmen 4 · 0⤊ 0⤋
4ab(9b-7)
2007-07-01 07:39:30 · answer #7 · answered by Anonymous · 0⤊ 0⤋
4ab(9b-7)
2007-06-29 16:53:55 · answer #8 · answered by sweetwater 7 · 0⤊ 0⤋
4ab(9b-7)
2007-06-29 16:50:42 · answer #9 · answered by johnsykes_2000 1 · 1⤊ 0⤋
4a(9b-7)b
2007-06-29 16:59:10 · answer #10 · answered by Atul Barapatre 2 · 0⤊ 0⤋