Simplify: (f^2 + 4f - 1) + (2f^2 - 3f + 2)?

Question

i really need help

Answer 1

(f^2 + 4f - 1) + (2f^2 - 3f + 2)
=f^2 + 4f - 1 + 2f^2 - 3f + 2
=f^2+ 2f^2+ 4f- 3f-1+2
=3f^2+f-1

Answer 2

Okay, this is no big deal. All you need to do is add together the like terms. To make this easier to digest, it can be rewritten and regrouped because the order of the terms doesn't matter in addition. 2+3+4 is the same as 4+3+2. Just pay attention to the sign changes. So, f^2 + 2f^2 + 4f - 3f - 1 + 2 is what you want to solve for. If it helps you visually, look at it like this... (f^2 + 2f^2) + (4f - 3f) + (- 1 + 2). Perform the operations in each set of parentheses individually. You should end up with (3f^2) + (f) + (1). Just get rid of the parentheses in your final answer. The idea is you keep the variable and exponent the same for like terms (whether it be f^2, f, or just a number) and you perform the given operation with the coefficient (the number in front of the variable).
I hope this helps!

Answer 3

3f^2+f+1