Does anyone know how to get the range
f(x) = 3Sin(2x)?
the answer is [-3,3] but I don't know how to get there.
Thanks
2007-06-29 09:24:54 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
we use the amplitude to find the range of a sin/cosine function
y = A cos/sin B (x - C) + D has the range of [ D + A, D - A]
so the range of 3sin(2x) + 0, is [0 + 3, 0 -3] ==> [3 , -3 ]
2007-06-29 09:32:20 · answer #1 · answered by 7 · 0⤊ 0⤋
You can get the answer by actually graphing the equation, or you can notice that range of any sin will be determined by the factor in front of it; in this case it is 3.
2007-06-29 09:29:05 · answer #2 · answered by red99 1 · 0⤊ 0⤋
f(x) = 3.sin 2x
max. value of sin 2x = 1
min. value of sin 2x = - 1
max.value of f(x) = 3 x 1 = 3
min. value of f(x) = 3 x - 1 = - 3
Range is [ - 3 , 3 ]
2007-07-03 03:57:48 · answer #3 · answered by Como 7 · 0⤊ 0⤋