6x + 1 > 5x
-2x + 8 < 11 + x
5x + 7 ≥ 4x + 4
4x + 2 < 3x - 1
how do i simplify these? i'm stuck on these certain ones.
i'm graphing them.
2007-06-29 09:11:09 · 4 answers · asked by Skyler 2 in Education & Reference ➔ Homework Help
Proceed as you would with an equation, collect like terms, etc. Recall: Multiplying or dividing by a negative #, changes the direction of the inequality sign.
6x + 1 > 5x
x > -1.
[Graph an open circle at x = -1 & shade in the direction of the inequality sign, to the right.]
-2x + 8 < 11 + x
-3x < 3
x > -1. [Mult./Divide by negative #, changes the direction of the inequality sign.]
5x + 7 ≥ 4x + 4
x ≥ -3.
4x + 2 < 3x - 1
x < -3.
2007-06-29 09:27:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
6x + 1 > 5x
subtract
X>-1
-2x + 8 < 11 + x
change sides
-3 < -3x
divide
x>1
5x + 7 ⥠4x + 4
subtract
x ⥠-3
4x + 2 < 3x - 1
subtract
X < -3
2007-06-29 16:13:36 · answer #2 · answered by ignoramus 7 · 0⤊ 0⤋
x>-1 so on the number line draw an open circle at -1 and then draw an arrow to the right.
x>-1 and that is the same as above
x>/=3 so on the number line draw a closed circle at 3 and then draw an arrow to the right.
x<-3 so on the number line draw an open circle at -3 and then draw an arrow to the left.
2007-06-29 16:28:42 · answer #3 · answered by sayamiam 6 · 0⤊ 0⤋
change the sign to equal, and get x alone on one side. if u had to divide by a negative at any point, change the sign to the opposite of wat it was. if u didnt divide by a negative, go back(from the = sign) to the sign it was before.
2007-06-29 16:14:44 · answer #4 · answered by Lauren 5 · 1⤊ 0⤋