In how many different ways can you deal out 5 red cards if you have a standard deck of 52 cards. I got 13!/8! but that is wrong because the answer is 7,893,600.
Thanks for the help!
2007-06-29 08:25:20 · 5 answers · asked by Icobes 2 in Science & Mathematics ➔ Mathematics
Hi,
You have 26 red cards out of 52 cards in the deck and you are selecting 5 of them.
It's 26nPr5 = 7,893,600
I hope that helps!! :-)
2007-06-29 08:30:13 · answer #1 · answered by Pi R Squared 7 · 0⤊ 1⤋
All we care about is the permuation of 5red cards out of a number of red cards. There are 26 reds cards, select 5 out of 26, the permuation is 26 x 25 x 24 x 23 x 22 = 7893600
2007-06-29 15:31:31 · answer #2 · answered by 7 · 0⤊ 0⤋
I'm not sure where you are getting the 8 from.
Half the cards are red, so P(26,5) = 26!/21! =
26*25*24*23*22 = 7,893,600
2007-06-29 17:08:11 · answer #3 · answered by Baysoc23 5 · 0⤊ 0⤋
There are 26 red cards in a pack (without jokers) -- hearts and diamonds.
If sequence is important, then 26P5 (which is the answer you give).
Otherwise, 26C5.
2007-06-29 15:33:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
26P5= 26!/21! = 7,893,600
2007-06-29 15:30:28 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋