20x^8 + 12x^4
____________
4x^2
2007-06-29 07:01:34 · 10 answers · asked by randall_gilmore 1 in Science & Mathematics ➔ Mathematics
20x^8 + 12x^4
____________
4x^2
factor out 4x^4
4x^4(5x^4+3)
____________
4x^2
x^2(5x^4+3)
2007-06-29 07:04:52 · answer #1 · answered by Carmen 4 · 1⤊ 0⤋
20x^8 / 4x^2 = 5x^6
12x^4 / 4x^2 = 3x^2
5x^6 + 3x^2 is the simplified expression of the above expression.
2007-07-03 01:38:25 · answer #2 · answered by Jun Agruda 7 · 2⤊ 0⤋
It is very simple.
Firstly we will do:
20x^8/4x^2 = 5x^6 [ By division, and a^m*a^n=a^(m+n) ]..........(1)
Secondly:
12x^4/4x^2 = 3x^2 [ Same as above.]....................(2)
Then we can add (1) and (2)
5x^6 + 3x^2 = x^2(5x^4 + 3)
2007-06-29 14:13:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
20x^8 + 12x^4
______________
4x^2
=4x^4(5x^4 + 3)
______________
4x^2
= 4x^4 (5x^4 + 3)
____
4x^2
= x^2 (5x^4 + 3)
2007-07-01 07:49:07 · answer #4 · answered by Anonymous · 0⤊ 0⤋
20x^8 + 12x^4
____________
4x^2
=4x^2(5x^6 + 3x^2)..............cancel 4x^2
____________
4x^2
=5x^6 + 3x^2
=x^2(5x^4 + 3)
2007-06-29 14:06:08 · answer #5 · answered by harry m 6 · 1⤊ 0⤋
x^2(5x^4+3)
2007-06-29 14:39:17 · answer #6 · answered by Rohit S 1 · 0⤊ 0⤋
x^2(5x^4+3)
2007-06-29 14:21:07 · answer #7 · answered by venkataramanan t 2 · 0⤊ 0⤋
5x^6 + 3x^2
x^2(5x^4 + 3)
2007-06-29 14:05:23 · answer #8 · answered by jay12645 2 · 1⤊ 0⤋
5x^6+3x^2
2007-06-29 14:04:25 · answer #9 · answered by maussy 7 · 0⤊ 2⤋
20x^8 + 12x^4
____________
4x^2
4x^2(5x^6+3x^2)
--------------------------
4x^2
ans is x^2(5x^4+3)
2007-06-30 00:25:33 · answer #10 · answered by Anonymous · 0⤊ 0⤋