find equation in standard form all inter coefficients of the line perpendicular to x+3y=6 passing through -3,5

0 ⤊

find equation in standard form all inter coefficients of the line perpendicular to x+3y=6 passing through -3,5

2007-06-29 06:00:47 · 1 answers · asked by deannahndrsn 2 in Science & Mathematics ➔ Mathematics

1 answers

lines perpendicular to x + 3y = 6 start out 3x - y = , and we get the = by plugging in the point:

3(-3) - 5 =
-9 - 5 =
-14

so 3x - y = -14

What on earth do you mean by all inter coefficients?

2007-06-29 06:06:00 · answer #1 · answered by Philo 7 · 0⤊ 0⤋