This is very important!!!! Please help!!!?

Question

5a^2/2 divided by 10b^2/3a^2



x+6/4 = 2x+3 / 3 - 2


solve for x: x^2 + x = 32 - 3x

Answer 1

5a^2/2 divided by 10b^2/3a^2
=5a^2/2 X3a^2/10b^2
=3 a^4/4 b^2

x+6/4=2x+3/3-2
or, x+6/4=(2x+3)/1
or,x+6/4=2x+3
or,x-2x=3-6/4
or, -x= 3/2
or x= -3/2 = -1 1/2

x^2+x=32-3x
or,x^2+x+3x-32=0
or,x^2+4x-32=0
or,x^2+8x-4x-32=0
or,x(x+8)-4(x+8)
or,(x+8)(x-4)=0
Therefore either x+8=0 or x-4=0
If,x+8=0,then x= -8
If,x-4=0.then x=4
Hence x= -8 or 4 ans

Answer 2

5a²/2 ÷ 10b²/(3a²) =
5a²/2 • 3a²/(10b²) =
(15a^4) / (20b²) =
3a^4 / 4b²

(x+6)/4 = (2x+3)/3 - 2
3(x+6) = 4(2x+3) - 24
3x + 18 = 8x + 12 - 24
5x = 30
x = 6

x² + x = 32 - 3x
x² + 4x - 32 = 0
(x + 8)(x - 4) = 0
x = -8 or x = 4