Why is it that when a pitcher pitches one out in an inning, its .1 of an inning, like if he pitched one out in the 6th inning, it would be 5.1 innings pitched, but it is 1 third of an inning. So wouldnt It be 5.3 I.P?
2007-06-29 04:05:46 · 7 answers · asked by Josh D 2 in Sports ➔ Baseball
It would, but when you are looking at it that way, it's bascially to say he has pitched 5 innings and there is 1 out in the 6th. Most people who follow baseball loosely, would find it confusing if it had 5.667 IP or 5.33 IP
Especially when ERA is a # that looks just like it. So, they simplify it to keep from confusing anyone.
2007-06-29 04:09:12 · answer #1 · answered by brianwerner1313 4 · 0⤊ 0⤋
No, because they count each out as one third of an inning, so if he pitched five complete innings and got one batter out in the sixth before leaving the game, he would have pitched 5.1 innings.
Chow!!
2007-06-29 12:06:10 · answer #2 · answered by No one 7 · 0⤊ 0⤋
It's just the way MLB and their stat services list the statistic.
5.1 means 5 and a third
5.2 means 5 and two-thirds.
In the days before computer typesetting, the agate pages of newspapers (the little type with the standings and boxscores and stuff) couldn't handle a number like "1/3" in an unambiguous way, so they started using the .1 and .2 to make them readable.
Also, it wouldn't be 5.3, it would be 5.3333333. . . . and nobody wants that in a boxscore. :-)
2007-06-29 12:08:32 · answer #3 · answered by pob14 4 · 0⤊ 0⤋
Innings are listed in trinary, not decimal, notation. This makes no difference for the complete innings, but it does make the sub-unary innings look weird. It's just a baseball thing, style of bookkeeping.
2007-06-29 11:25:41 · answer #4 · answered by Chipmaker Authentic 7 · 0⤊ 0⤋
u lost me at the ?
2007-06-29 12:00:12 · answer #5 · answered by Marc_R 3 · 0⤊ 0⤋
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2007-06-29 11:49:54 · answer #6 · answered by baseballrocks 1 · 0⤊ 1⤋
idk u lost me and i suck at math
2007-06-29 11:09:07 · answer #7 · answered by greg g 5 · 0⤊ 0⤋