only at mcdonalds
2007-06-29 02:57:04
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answer #1
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answered by Anonymous
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Yes, it does happen. Somebody operating such an access point can easily read all of your (unencrypted) traffic. A sophisticated scammer will also employ fake DNS computers to route you to counterfeit servers that look like real destination servers (like Facebook, or Yahoo!). In this manner, they can even get your encrypted traffic. It's also possible that these counterfeit servers could install viruses on your computer that will persist, even after you leave the "free" wi-fi. Practice safe computing: know who you interface with!
2016-04-01 10:20:26
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answer #2
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answered by Anonymous
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At some hotspots it's free like barnes and noble.
There are many open routers thought that can give you free wireless internet. However, it's often a mistake made by people and unauthorized use is technically illegal. (However, 99.9999999999999999999% you won't get caught)
Other routers are secured by encryption that you can't log into without a password.
2007-06-29 02:58:20
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answer #3
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answered by Anonymous
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It depends on the service. If there is a charge, it usually comes in the form of a web page where you enter billing information before you can surf the web.
You can connect for free, but I'd be wary of any unfamiliar connections. You may just be inviting hackers.
2007-06-29 02:58:41
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answer #4
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answered by Marty B 3
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If it is advertised as being free, then yes. Most places like coffee shops and whatnot are usually free.
2007-06-29 02:57:52
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answer #5
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answered by Yoi_55 7
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Free for me, i do it on my ds at home using a wireless router? Doesnt cost a cent!
2007-06-29 02:57:55
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answer #6
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answered by Anonymous
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It is if the place offering it is doing it for free.
2007-06-29 02:57:22
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answer #7
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answered by togashiyokuni2001 6
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http://answers.yahoo.com/question/index;_ylt=AhxVj9feC7.FUX0PZ3ocLK7ty6IX?qid=20070626081352AAR9Tvq&show=7#profile-info-e86200ded8db353ac9bef0f582c8f13aaa
2007-06-29 02:58:24
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answer #8
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answered by lancej0hns0n 4
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yes of course......lol
2007-06-29 02:57:34
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answer #9
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answered by Anonymous
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