2007-06-29 01:49:09 · 14 answers · asked by lindasalicea 1 in Science & Mathematics ➔ Mathematics
18x^3-36x^2
= (18x^2)(x) - (18x^2)(2)
= (18x^2)(x - 2)
2007-06-29 01:53:27 · answer #1 · answered by Mathematica 7 · 0⤊ 2⤋
first 36 = 2*18
so 18x^3-36x^2= 18(x^3-2x^2)
you put x^2 in factor
18x^2(x-2)
2007-06-29 09:20:53 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
Its pretty simple. Take out the common factors out.
18x^3-36x^2
18x^2(x-2)
2007-06-29 09:01:20 · answer #3 · answered by lasweettruca 2 · 0⤊ 1⤋
18x^3 - 36x^2
= 6x^2(3x-6)
or
= 3x^2(6x-12)
or
= 18x^2(x-2)
2007-07-03 07:50:32 · answer #4 · answered by gostob2 3 · 0⤊ 0⤋
18x^3 - 36x^2
(18x^2) * (x - 2)
2007-07-03 05:52:32 · answer #5 · answered by Jun Agruda 7 · 1⤊ 0⤋
18x^2(1x-2)
Answer : 1x-2
Simply divide by 18 x^2 because it is the greatest common factor.
2007-06-29 16:28:10 · answer #6 · answered by Kandice F 4 · 0⤊ 0⤋
Given:
18X^3-36X^2
18(X^3-2X^2)
18{X^2(X-2)}
18X^2(X-2)
2x9xX^2(X-2)
2x3^2xX^2(X-2)
2(3X)^2(X-2).......Ans
2007-07-03 04:49:20 · answer #7 · answered by Joymash 6 · 0⤊ 0⤋
18x^3-36x^2=18x(1^3-2^2)
=18x(1-4)
=18x(-3)
=-54x
2007-06-29 10:07:15 · answer #8 · answered by Anonymous · 0⤊ 0⤋
18x^3-36x^2
=x^2(18x-36)
=18x^2(x-2)
2007-06-29 08:54:11 · answer #9 · answered by dismuhghettoname 4 · 0⤊ 1⤋
18 x^2 (x - 2 )
2007-06-29 09:18:57 · answer #10 · answered by CPUcate 6 · 0⤊ 0⤋