English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

be mixed to obtain a total of 131 Liters @ 27% solution of HCl.







(I'm ABOUT TO GO CRAZY WITH THIS LAST QUESTION!!)

2007-06-28 19:43:37 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

A chemist has two solutions of HCl (one is 40% and other is 25% concentrate) how many liters of each needs to be mixed to obtain a total of 131 Liters @ 27% solution of HCl.

Let
x = amount 40% solution
131 - x = amount 25% solution

.40x + .25(131 - x) = .27*131
.40x + .25*131 - .25x = .27*131
.15x = .02*131
15x = 2*131 = 262
x = 262/15 = 17 7/15

131 - x = 131 - 17 7/15 = 113 8 /15

You need 17 7/15 liters of 40% solution and 113 8/15 liters of 25% solution.

2007-06-28 20:21:40 · answer #1 · answered by Northstar 7 · 0 0

tip to solve solution concentration
amount (HCL) in sol A + amount(HCL) in sol B = amount (HCL) in sol C

Solution A: 40% concentration
solution B: 25%
solution C: 27%

Let X be the volume (in liters) of the solution A
and Y be the volume of solution B: Y = 131 - x
and volume of solution C: 131 liters


the amount of HCL in solution A: .4x
the amount of HCL in solution B: (131 -x) * .25 = 32.75 - .25x
the amount of HCL in the final solution C: 131 * .27 = 35.37

.4x + (32.75 -.25x) = 35.37
.15 x = 2.62

solve for x = 17.47 (in solution A)

Y = 131 - 17.47 = 113.53

2007-06-29 13:41:13 · answer #2 · answered by buoisang 4 · 0 0

Assuming additive volumes (which isn't always accurate):

0.4A + 0.25B = 0.27(A+B)
(mass conservation for HCL)

A+B = 131
(Additive volumes assumption)
Do the math.

2007-06-29 02:49:41 · answer #3 · answered by Israfel 3 · 0 0

fedest.com, questions and answers