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a. f(x) = (x + 1)/(2x + 4)

b. g(x) = 2x/(x2 - 4)

c. h(x) = (x2 + 4x + 15)/(x + 2)

d. F(x) = (x3 - x - 1)/[(x - 1)(x + 2)]

e. G(x) = (x3 )/(x - 4)

f. none of these

2007-06-28 18:28:57 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

A function with a vertical asymptote approaches infinity as x approaches some point which generally arises when there is division by 0 at the point x approaches. So a function with 2 vertical asymptotes will have division by 0 at 2 points so we look for a function which has a quadratic term with 2 real roots in the denominator.

(b) and (d) have quadratics in their denominators with 2 distinct real roots so they each have 2 vertical asymptotes. However, (d) does not have a horizontal asymptote since

lim F(x) = ±∞
x->±∞

(b) has 1 horizontal asymptote since

lim g(x) = 0
x->±∞

So (b) has 2 vertical asymptotes at x=±2 and a horizontal asymptote at x=0

2007-06-29 02:33:00 · answer #1 · answered by Astral Walker 7 · 1 0

b) x=2 and x=-2 are the vertical aysimptotes and y=0 the horizontal one

2007-06-29 14:20:33 · answer #2 · answered by santmann2002 7 · 0 0

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