Evaluate: 5squareroot-1
and
please simplify:(x^4/3)^6
2007-06-28 17:51:58 · 5 answers · asked by Peqo 1 in Science & Mathematics ➔ Mathematics
5 sqrt(-1) = 5i which is a complex number
(x^4/3)^ 6 = x^8
(becoz 4/3 * 6 = 4*2=8)
2007-06-28 17:57:55 · answer #1 · answered by Aruna R 2 · 1⤊ 0⤋
Problem 1
squareroot(-1) = i
5squareroot(-1) = 5i
Answer: 5i
Problem 2
(x^(4/3))^6
= x^[ (4/3)6 ]
= x^[ 24/3 ]
= x^8
Answer: x^8
2007-06-29 01:00:26 · answer #2 · answered by mathjoe 3 · 0⤊ 0⤋
5squareroot-1=5i
(x^4/3)^6=x^(4x6/3) = x^x^8
2007-06-29 00:59:10 · answer #3 · answered by Anonymous · 0⤊ 0⤋
sqrt(-1) is something we call an imaginary number. We use the symbol " i " to represent this value.
So 5 sqrt(-1) = 5 * sqrt(-1) = 5i
(x^4/3)^6 = x^(4/3 * 6)
= x^8
I hope this helps!
2007-06-29 00:59:35 · answer #4 · answered by math guy 6 · 0⤊ 0⤋
5sqrt(-1) = 5i
(x^4/3)^6 = x^24/3 = x^8
2007-06-29 01:04:20 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋