Punnett Squares?

Question

I posted a question before asking about how to find genotype percentages and phenotype percentages and I did get much detail, but not quite the answer I needed.

This time I'll try to be more specific and ask for what I want.

Given pea plants such that the pea color yellow is dominant and the green color is recessive, the pea shape round as dominant and pea shape wrinkled as recessive, the pea color use C for dominant and c for recessive, S for dominant for pea shape and s for recessive.

If I asked for the genotype percentages and the phenotype percentages of the offspring of CcssXCCSS, how would I calculate it Mathetically?

Answer 1

Think of the Cc x CC part. 1/2 offspring would be Cc and 1/2 would be CC.

Think of the ss x SS part. All offspring would be Ss.

That means that 1/2 would be CcSs and 1/2 would be CCSs.

Answer 2

P1 CcssXCCSS
find possible outcomes of gametes
1/2Cs + 1/2 cs X 1/1 CS
The first parent can give either a 'C' or a 'c' but will always give a 's.' The second parent can only give a C and S.

multiply. (find 1/2Cs times 1/1 CS plus 1/2 cs times 1/1 CS)
F1= 1/2CCSs + 1/2 CcSs(genotype)
1/1 Yellow round(pheno)

Answer 3

First you would have to figure out how many different combinations of these genes the parents could produce by meiosis when forming gametes. An individual that was Ccss could produce only two types: Cs or cs, while the CCSS individual could produce only one type, CS. Then you have to figure out what phenotype each type of egg being fertilized by each type of sperm would produce.
If the match were Cs x CS, the individual would be yellow round. If the match were cs x CS, that individual would also be yellow round. Therefore, 100% of the offspring would be yellow round.