Find the derivative of 3x^2 - 2/x?

1 ⤊

2007-06-28 15:50:56 · 5 answers · asked by Toves 1 in Science & Mathematics ➔ Mathematics

6x + 2x^-2

2007-06-28 15:59:57 · answer #1 · answered by Anonymous · 1⤊ 0⤋

y = 3x^2 - 2/x
y' = 6x + 2/x^2

2007-06-28 15:58:55 · answer #2 · answered by cllau74 4 · 0⤊ 0⤋

3x^2 - 2/x=3x^2 - 2x^(-1)
derivative: 2*3x^(2-1)-(-1)*2x^(-1-1)
6x^1+2x^(-2)
6x+2/(x^2)

2007-06-28 16:10:15 · answer #3 · answered by Arfianto M 2 · 0⤊ 0⤋

Both terms derivitives are found by the power law rule. Since they are added, their derivitives are added. So.....
answer is 6x + 2/x^2

2007-06-28 15:59:02 · answer #4 · answered by cattbarf 7 · 0⤊ 0⤋

f(x) = 3.x² - 2.x^(-1)
f `(x) = 6x + 2.x^(-2)
f `(x) = 6x + 2 / x²

2007-07-02 08:03:17 · answer #5 · answered by Como 7 · 0⤊ 0⤋