2007-06-28 13:28:03 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
16 k^2 + 24 K + 9 =
(4K +3)^2
2007-06-28 13:31:59 · answer #1 · answered by telsaar 4 · 0⤊ 0⤋
16k^2+24k+9
16k^2+12k+12k+9
Group the expression
(16k^2+12k)+(12k+9)
Factor the groups
4k(4k+3)+3(4k+3)
Now you have
(4k+3)(4k+3)
This may seem obvious, but since you are multiply the same thing togther you square them.
(4k+3)^2
2007-06-28 20:33:27 · answer #2 · answered by UnknownD 6 · 0⤊ 0⤋
16K^2 + 24K + 9
= (4K)^2 + 24K + (3)^2
= (4K + 3)^2
2007-06-28 20:44:03 · answer #3 · answered by Kemmy 6 · 0⤊ 0⤋
16k² + 24k + 9
= (4k + 3).(4k + 3)
= (4k + 3)²
2007-07-02 15:07:53 · answer #4 · answered by Como 7 · 0⤊ 0⤋
(4k+3)^2
2007-06-28 20:32:30 · answer #5 · answered by ? 5 · 0⤊ 0⤋
John Cena and Randy Orton
2007-06-28 20:30:21 · answer #6 · answered by Anonymous · 3⤊ 0⤋
(4K+3)(4K+3)
2007-06-28 20:32:27 · answer #7 · answered by Anonymous · 0⤊ 0⤋
I AGREE WITH DX
2007-06-28 20:32:18 · answer #8 · answered by Anonymous · 0⤊ 0⤋