y = -2
as both coordinates have y values of -2.
2007-06-28 13:06:35
·
answer #1
·
answered by Kemmy 6
·
1⤊
0⤋
y = 2 ?
2007-07-01 06:20:22
·
answer #2
·
answered by J 1
·
0⤊
0⤋
In slope-intercept form, the equation of a line is y = mx + b.
m = slope = rise/run = (change in y)/(change in x).
In this case, the change in y is 0, and the change in x is 1.
So slope is 0/1 = 0. Hence, mx = 0
So the equation turns into y = b.
Since y (at both points) is -2, b = -2.
The equation of the line is y = -2.
2007-06-28 20:07:53
·
answer #3
·
answered by Bramblyspam 7
·
0⤊
0⤋
generally, equation for line is "y=ax+b" where x and y are coordinates and a,b are constants. so you have to find these constants to find the equation. since the 2 points (3,-2) and (4,-2) are on the line, their coordinates satisfy the equation, so you know that these two equations are true at the same time:
-2=3a+b
-2=4a+b
resolving:
-2=3a+b => b=-2-3a
-2=4a+b => -2=4a-2-3a=> a=0
a=0
-2=3a+b => -2=3.0+b => b=-2
so you have y=0.x -2 that is y=-2 is the equation
2007-06-28 20:11:58
·
answer #4
·
answered by akkinoref 1
·
0⤊
0⤋
This is a horizontal line i.e. a line with no gradient.
Equation is y = - 2
2007-06-29 04:15:56
·
answer #5
·
answered by Como 7
·
0⤊
0⤋
you can do it by the low (y1-y2 divided x1-x2) so it will be (-2+2)divided(3-4)=0 so this is the slope & then you have to make dy/dx=slope & solve it..!!
2007-06-28 20:12:23
·
answer #6
·
answered by sose 2
·
0⤊
0⤋
y=b
the slope is 0 so x is 0.
y=0 times0 +b so
y=b
am i right?
2007-06-28 20:11:16
·
answer #7
·
answered by Tameron S 1
·
0⤊
0⤋