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7 answers

y = -2
as both coordinates have y values of -2.

2007-06-28 13:06:35 · answer #1 · answered by Kemmy 6 · 1 0

y = 2 ?

2007-07-01 06:20:22 · answer #2 · answered by J 1 · 0 0

In slope-intercept form, the equation of a line is y = mx + b.
m = slope = rise/run = (change in y)/(change in x).
In this case, the change in y is 0, and the change in x is 1.
So slope is 0/1 = 0. Hence, mx = 0
So the equation turns into y = b.

Since y (at both points) is -2, b = -2.

The equation of the line is y = -2.

2007-06-28 20:07:53 · answer #3 · answered by Bramblyspam 7 · 0 0

generally, equation for line is "y=ax+b" where x and y are coordinates and a,b are constants. so you have to find these constants to find the equation. since the 2 points (3,-2) and (4,-2) are on the line, their coordinates satisfy the equation, so you know that these two equations are true at the same time:
-2=3a+b
-2=4a+b
resolving:
-2=3a+b => b=-2-3a
-2=4a+b => -2=4a-2-3a=> a=0

a=0
-2=3a+b => -2=3.0+b => b=-2

so you have y=0.x -2 that is y=-2 is the equation

2007-06-28 20:11:58 · answer #4 · answered by akkinoref 1 · 0 0

This is a horizontal line i.e. a line with no gradient.
Equation is y = - 2

2007-06-29 04:15:56 · answer #5 · answered by Como 7 · 0 0

you can do it by the low (y1-y2 divided x1-x2) so it will be (-2+2)divided(3-4)=0 so this is the slope & then you have to make dy/dx=slope & solve it..!!

2007-06-28 20:12:23 · answer #6 · answered by sose 2 · 0 0

y=b
the slope is 0 so x is 0.
y=0 times0 +b so
y=b

am i right?

2007-06-28 20:11:16 · answer #7 · answered by Tameron S 1 · 0 0

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