In the period of a year, an investor lost twice as much as he gained. If he originally had $10,000 and how has $8000, what amount did he gain and what did he lose?
Could you please help me out with this problem and explain it to me?
2007-06-28 11:45:56 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Let x = the amount he gained
So 2x = the amount he lost
10,000 - 2x + x = 8,000
10,000 - x = 8,000
-x = -2,000
x = 2,000
He gained $2,000 and lost twice that or $4,000
Check: 10,000 + 2,000 - 4,000 = 8,000
2007-06-28 11:51:33 · answer #1 · answered by Kathryn 6 · 0⤊ 0⤋
Hello
He gained 2000 and lost 4000. The way to solve this is setup the equation for before the loss which is 10000+x=y
Then the equation for after the loss is 10000-x=8000
So therefore he gained 2000 and lost 4000.
I hope this helped! See ya.
2007-06-28 11:56:51 · answer #2 · answered by Archmage 2 · 0⤊ 0⤋
If he gained X amount of money, then lost 2X amount of money, it's the same as losing X amount of money. We can see from his initial and final totals that he has lost $2000. So, he therefore gained $2000 and lost $4000.
2007-06-28 11:51:24 · answer #3 · answered by lithiumdeuteride 7 · 0⤊ 0⤋
10000 + x -2x = 8000
x = 2000
(He gained 2000 and lost 4000)
2007-06-28 11:52:23 · answer #4 · answered by Anonymous · 0⤊ 0⤋
He gained x
He lost 2x
10000 + x - 2x = 8000
10000 - x = 8000
x = 2000
2x = 4000
He gained $2000
He lost $4000
2007-06-28 11:54:00 · answer #5 · answered by gudspeling 7 · 0⤊ 0⤋