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v(t)= sqrt[ gm/k ] tanh[ (kg/m)t ]

2007-06-28 11:22:28 · 4 answers · asked by azulita 3 in Science & Mathematics Mathematics

4 answers

If v is just a function of t and the other varibles are all constants, then this is just integrating something in the form of
∫ a tanh(bt) dt, where a = √(gm/k) and b=(kg/m). In this case you'd have:
∫ a tanh(bt) dt =
a ∫ tanh(bt) dt =
(a/b) ∫ tanh(bt) * b dt =
(a/b) ln(cosh(bt)) + C

2007-06-28 11:34:04 · answer #1 · answered by Anonymous · 0 0

This same question was asked earlier today... weird
Anyways, the answer was ln |cosh(sqrt(kg/m)t)| + C

http://answers.yahoo.com/question/index;_ylt=Ar6WuM66_2XuLT.5QW..J.Tsy6IX?qid=20070628093634AA0tHiT&show=7#profile-info-w30NDszGaa

2007-06-28 18:33:51 · answer #2 · answered by hawkeye3772 4 · 1 0

Integrating that function with respect to t, you get:

m/(g*k) * sqrt[g*m/k] * log[cosh[k*g/m * t]]

2007-06-28 18:35:28 · answer #3 · answered by lithiumdeuteride 7 · 0 0

ln|cosh[(kg/m)*t]|*sqrt[(m/k)^3*1/g]

2007-06-28 18:52:08 · answer #4 · answered by Anonymous · 0 0

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