please help!?

Question

6: Skeeter the Wonder Dog jumps through circular rings as part of his dog show exhibition. Skeeter requires a width of 18 inches for his costume to clear the ring. Will a ring with an inner circumference of 39.8 inches be large enough for Skeeter's act?
yes
no
not enough information
maybe


7: A large pizza has a circumference of 72.5 inches. Which of the perimeters listed belongs to the smallest box capable of holding a large pizza?
23
24
73
96


8: Find the width of a rectangular vegetable garden if its perimeter is 16.4 m and its length is 5.05 m.
3.15 m
5.05 m
6.3 m
10.1 m


9: A rectangular football field has side lines 120 yards long. Each of the end lines is 160 feet long. What is the perimeter of the football field?
280 ft
346 ft
880 ft
1040 ft


10: The perimeter of a rectangle is 46 feet. I need to get from point A to point B. What is the shortest distance from A to B? A to B is the diagonal and you know the longer side of the rectangle has length = 15 feet.
8 ft.
15 ft.
16 ft.
17 ft.

Answer 1

6. Circumference = 2 * pi * radius. Diameter = 2 * radius = 18 inches. Solve for the radius and see if the diameter is big enough.

7. Circumference = 2 * pi * radius. Diameter = 2 * radius = width of the box necessary to hold the pizza. Perimeter of box = 4 * width of the box. Solve for the width.

8. Perimeter = 16.4m = 2 * length + 2 * width. Plug in length and solve for width.

9. Perimeter = 2 * length + 2 * width

10. Perimeter = 2 * length + 2 * width. Use the Pythagorean Theorem to calculate the diagonal after you calculate the width.

Answer 2

Remember that for a circle, C = π d (circumference is π times the diameter)

6. The diameter of the hoop is d =C/π, or 39.8 / π, which is about 12.66 inches. That's not wide enough.

7. When you put a pizza in a square pizza box, the diameter of the pizza is about the same as the length of the box. So the perimeter of the box has to at least be 4 times the pizza's diameter. Use C= π d to find the diameter like before, then multiply by 4 to find the perimeter of the smallest square box that could hold the pizza.

8. The opposite sides of a rectangle are the same. So if the length is 5.05m and the width is some unknown "w", then the perimeter is 5.05 + 5.05 + w + w, or 10.1 + 2w. Set this equal to the perimeter (16.4 m) and solve for w.

9. Convert the yards into feet first, then use the same 2L + 2W forumula for finding a rectangle's perimeter

10. Find the width the same way you found it in #8. Then use the Pythagorean theorem to find the distance of A to B.

Answer 3

d = 39.8/pi = 12.67. No. needs to be > 18 inches

96 inches assuming box is square.

width (16.4 - 2(5.05))/2 = 3.15m

120*3*2 + 160*2 = 720 + 320 = 1040 feet

width = (46-30)/2 = 8 feet
So AB = diagonal = sqrt(8^2+15^2) = 17

Answer 4

6) Not enough room (12.66 inches)

7) Perimeter needed is 91.6 so the answer is 96inches

8) 6.3m

9) There's 3 feet in a yard right? (UK answerer here!) 1040 feet

10) 17 feet