(3x/2)-1 = 2- ((x+1)/5))
The answer is suppose to be x= 28/17
But what is the most simple way to solve this problem?
2007-06-28 10:28:19 · 6 answers · asked by korr 2 in Science & Mathematics ➔ Mathematics
ok so first multiply both sides by 10 to get rid of fractions
by doing that we get
15x-10=20-2x-2
then just simplfy
17x=28
2007-06-28 10:32:55 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Mult each term(both sides) by LCD (10) and that clears out fractions.
10[ (3x/2) - 1 = 2 - (x+1)/5] 10
15x - 10 = 20 - 2(x+1) distribute
15x - 10 = 20 - 2x - 2 collect like terms
17x = 28
x = 28/17
2007-06-28 10:35:50 · answer #2 · answered by ktm 3 · 0⤊ 0⤋
move the x values to one side
3x / 2 + [(x + 1) / 5] = 3
use common denominator 10
15x + 2x + 2 = 30
17x = 28
x = 28 / 17
Jesus I'm tired
2007-06-28 10:33:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(3x) / 2 - 1 = 2 - (x + 1) / 5------- (X by 10)
15x - 10 = 20 - 2.(x + 1)
15x - 10 = 20 - 2x - 2
17x = 28
x = 28 / 17
2007-07-02 04:59:17 · answer #4 · answered by Como 7 · 0⤊ 0⤋
3x/2-1=2-(x+1/5)
3x-2=4-2x-2/5
5x=28/5
x=28/25.answer
2007-06-28 11:12:14 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I don't know how to say it in English (I'm Peruvian), but umm.. Multiply all the numbers by 10 and then just add or substract :)
2007-06-28 10:32:11 · answer #6 · answered by ViCtoria 3 · 1⤊ 0⤋