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Simplify 4sin2xcos2x. Please explain steps. Thanks

2007-06-28 10:07:21 · 3 answers · asked by Deborah P 2 in Science & Mathematics ➔ Mathematics

Let A = 2x
4.sin 2x.cos 2x
= 4.sin A.cos A
= 2.(2 sin A.cos A)
= 2.sin 2A
= 2.sin 4x

2007-07-02 04:54:39 · answer #1 · answered by Como 7 · 0⤊ 0⤋

we have the identity sin2x = 2 sin x cos x
so 4 sin 2x cos 2x = 2 sin 4x

2007-06-28 17:12:13 · answer #2 · answered by hipguyrockin 2 · 0⤊ 0⤋

sine the double of the angle:sin2x=2sinxcosx
similarly:sin4x=2sin2xcos2x
therefore 4sin2xcos2x=2(2sin2xcox2x)
=2*sin4x
=2sin4x

2007-06-28 17:14:45 · answer #3 · answered by D 2 · 0⤊ 0⤋