find the equation in standard form with all interger coefficients of the line perpendicular to x +3y =6 and?

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find the equation in standard form with all interger coefficients of the line perpendicular to x +3y =6 and?

passing through (-3,5). I know the answer is not b= 14

2007-06-28 08:34:36 · 3 answers · asked by peaches 1 in Science & Mathematics ➔ Mathematics

3 answers

x + 3y = 6

x + 3y - x = - x + 6

3y = - x + 6

3y / - x / 3 + 6 / 3

y = - x/3 + 2

Slope = 1/3

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Slope Intercept form

y = mx + b

Ordered Pair

( - 3, 5)

5 = 1/3(- 3) + b

5 = - 3/3 + b

5 = - 1 + b

5 + 1 = - 1 + b + 1

6 = b

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The equation

y = 1/3x + 6

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2007-06-28 10:06:27 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋

1/3x -y= 6 i think.

2007-06-28 15:45:51 · answer #2 · answered by .:oh happy day:. 2 · 0⤊ 0⤋

3x-y = -14

2007-06-28 15:39:34 · answer #3 · answered by autigerjoie 2 · 0⤊ 0⤋