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2 answers

1 gram of Silver takes 0.06 cal to rise the temperature of 1 °C

Example
g of Silver = 10
T1 = 30 °C
T2 = 60 °C
calories = 10 g x ( 60°C - 30°C ) x 0.06 cal / g C = 18 cal

You can find more informations on :
http://en.wikipedia.org/wiki/Specific_heat

2007-06-28 08:12:12 · answer #1 · answered by Dr.A 7 · 0 0

If you want to raise 10gAg by 10degC, then:

10gAg x 10C x 0.06cal/gC = 6 cal

The g and C cancel out, leaving cal.

2007-06-28 15:14:12 · answer #2 · answered by steve_geo1 7 · 0 0

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