Estriol, a potent estrogenic hormone, has been isolated from the urine of pregnant women. When 40mg of estriol is dissolved in 1.0 mL of dioxane and placed in a sample tube with 1 dm path length a rotation of +2.32 degrees is observed. Calculate the specific rotation for estriol.
2007-06-28 07:21:30 · 2 answers · asked by annhall90 1 in Science & Mathematics ➔ Chemistry
Use this equation and plug and chug.
[specific rotation] = (alpha x 100)/(l x c)
alpha = 2.32
l = path length in dm = 1 dm
c = concentration in g /mL = 0.040 g/mL
Enter these numbers and do the arithmetic and you will have your answer. Good luck. I hope this helps.
2007-06-28 07:48:33 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Sp. Rotation = 100 x Exp. Rotation/Lc
L = length of tube in decimeters; c = concentration in g/100mL solution.
Let estriol be called E. Let solution be called S. 40mgE/1.0mLS x 100 = 0.4gE/100mLS
Sp. Rotation = (+2.32)(100)/(1)(0.4) = 580deg
An answer greater than 360 deg seems silly, but specific rotations often come out that way. This is because there are several asymmetric atoms in estriol, so the molecule has enormous rotatory power. Specific rotations of some asymmetric cobalt complexes come out in the 1000's of deg.
2007-06-28 14:39:27 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋