2007-06-28 05:36:45 · 4 answers · asked by 23344 2 in Science & Mathematics ➔ Mathematics
y = (-1/3)x + 5
Any line perpendicular to the original will have a slope that is the negative reciprocal of the original slope. Since the original slope is 3, any line with a slope of (-1/3) will be perpendicular to it.
2007-06-28 05:39:35 · answer #1 · answered by MamaMia © 7 · 0⤊ 0⤋
If it's perpendicular, then the slope is the negative reciprocal of the original slope. So the perpendicular line is:
y= - (1/3)x + c
The c can be any constant you like, for example zero.
2007-06-28 12:45:19 · answer #2 · answered by mikeburns55 5 · 0⤊ 0⤋
given a line
y = mx + b
equation of a line that is perpedicular to this line is
y = (-1/m) x + c
so: y = (-1/3)x + c
2007-06-28 17:33:39 · answer #3 · answered by buoisang 4 · 0⤊ 0⤋
perpendicular lines have opposite reciprocal slopes
your slope is 3
perpendicular slope is -1/3
y=(-1/3)x+b, for some value b
2007-06-28 12:40:52 · answer #4 · answered by hrhbg 3 · 0⤊ 0⤋