For function to be a metric it has to satisfy
a) D(x, x) >=0
b) D(x, y) = D(y, x)
c) D(x, y) <= D(x, z) + D(z,y)
if d is a metric, then
d(x, x) > = 0 and D(x, x) = d(x, x) + 4 is also > = 0
Also
D(x, y) = d( x, y) + 4 = d(y, x) + 4 = D(y, x).....since d itself is a metric.
and D(x, y) = d(x, y) + 4 < = d( x, z) + d(y, z) + 4 < =
d(x, z) + 4 + d( y, z) + 4 = D(x, z) + D(y,z)
It satisfies all three properties, hence it is also a metric.
2007-06-28 05:16:55
·
answer #1
·
answered by swd 6
·
0⤊
0⤋