Solve each system by the substitution method?

Question

x=4y-2
x=6y+8

Answer 1

x=4y-2
x=6y+8


4y - 2 = 6y + 8
4y - 2 - 8 = 6y + 8 - 8
4y - 10 = 6y
4y - 4y - 10 = 6y - 4y
-10 = 2y

y = -10/2 = -5

x = (4y - 2) = (-20 - 2) = -22

Answer 2

First pick a variable to solve for. It is easier to pick x because in the problem it is equal to something in the original problem.
Since x=4y-2, substitute the 4y-2 in the place of x in the second problem so it looks like this:
4y-2=6y+8
Then what you do is put the like terms together. This means you put the y's together and the constants or numbers together. Then you would end up with this:
4y-6y=2+8
Then you simply solve. it then looks like this.
-2y=10
You have to get a solution for y not -2y so divide both sides by -2 so it looks like this.
y=-5
What you do after that is put -5 in the place of the y in the first equation which gives you this:
x=4(-5)-2
Which simplifies to..
x=-20-2
x=-22
Then you put the two answers in the form of an ordered pair which gives you (-22,-5).
I hope this helped!!
If you don't mind, I'd like to ask you a bit of a personal question. What grade are you in because we learned this stuff in the 8th grade!!

Answer 3

4y - 2 = 6y + 8
2y = - 10
y = - 5

x = - 20 - 2
x = - 22

Solution is x = - 22 , y = - 5

Answer 4

x=4y-2
So,
..4y=x+2
..y=(x+2)/4

Now, put this in oter equation
x=6y+8
=6(x+2)/4+8
=3/2*(x+2)+8
=[(3x+6)+16]/2
so,
2x=3x+6+16
2x=3x+22
so,x= -22

Now put x=(-22) in any given equation and you will get y=(-5).
You can also do by taking other equation first. This is the method of substitution.

Answer 5

x=4y-2
x=6y+8

4y-2=6y+8
-2y=10
y=-5

x=4(-5)-2
x=-20-2
x=-22

(-22,-5)