If the side of the square is increased by 20% then the area of the square is increased by?

Answer 1

20% increase means multiplying by 1.20
you get the are by squaring the length of the side
if you square 1.20, you get 1.44
which is equal to 44% increase

Edit: or, more mathematically:

S = a^2
a' = a + 20%*a=1.20*a
S' = a'^2 = (1.20*a)^2 = 1.44*a^2 = 1.44*S = S + 44%*S

Answer 2

The full unit is 100% or 1.
1² = 1 Square unit.

1∙2 is a 20% increase of the lenght of the side.
(1∙2)² = 1∙44
That is , 144%.
144% - 100% = 44%.

Answer 3

let the side of a square be a then the area is a^2.
if the side is increased by 20% it becomes 120a.
then the area will be 14400a^2.
hence the area is increased by 144%.

Answer 4

Area of square of side x = x²
Area of square of side 1.2x = 1.2x X 1.2x = 1.44x²
Increase in area = 1.44x² - x² = 0.44x²
ie an increase of 0.44x²/x² X 100% = 44%

Answer 5

let the side of the squarebe x
areaA=x^
If the side of the square is increased by 20%,it becomes 1.2xand the areaA+DA becomes=1.2^2x^2=1.44x^2=1.44A
increase in area=DA=.44A
% increase in area=.44A/A x100=44% answer.

Answer 6

that's easy but first you've got to know the size of the square before the increment.but i think i can work it.
area of a square= Length multiplied by length
=L*L
=L square multiplied by 20%

Answer 7

let, l=x unit
then A= l*l= x^2 sq. unit
now l1= x+0.2x=1.2x
so,A1= l1*l1=1.44 sq.unit
now % increase in a= (A1-A)*100/A
=44
Ans.

Answer 8

44%

Answer 9

44%

Answer 10

20%, believe me.