Can someone help me with this math problem?

Question

Solve for x using quadratic formula
2x^2+3x-2=0
Please list the steps. Thank you.

Answer 1

2x^2 + 3x - 2 = 0

Quadratic formula:

x = ( -b +/-sqrt b^2 - 4ac)/ 2a

In our equation:
a = 2
b = 3
c = - 2
Substitute the above values in the equation:

x = ( -b +/- sqrt b^2 - 4ac)/ 2a
x = ( -3 +/- sqrt3^2 - 4(2)(-2))/ 2(2)
x = (-3 +/- sqrt 9 - (-16))/ 4
x = (-3 +/- sqrt 9 + 16))/4
x = (-3 +/- sqrt 25)/4
x = (-3 +/- 5)/4
x = (-3 + 5)/4 = 2/4 = 1/2 and
x = ( -3 - 5)/4 = -8/4 = -2
So x = 1/2 and -2

Answer 2

Write the quadratic equation in standard form, ax^2 + bx + c = 0.
2x^2 + 3x - 2 = 0

Identify a, b, and c.
a = 2, b = 3, and c = -2

Substitute the values of a, b, and c into the quadratic formula, x = [ -b +or- sqrt( b^2 - 4ac) ] / [ 2a ].
x = [ -(3) +or- sqrt(3^2 - 4(2)(-2) ] / [ 2(2) ]

Simplify.
x = [-3 +or- sqrt(9 + 16) ] / 4
x = [-3 +or- sqrt(25) ] / 4
x = [-3 +or- 5 ] / 4

Write the two separate equations implied by the + or- symbol and solve for the two values of x.
x = [-3 + 5 ] / 4 or x = [-3 - 5 ] / 4
x = 2 / 4 or x = -8 / 4
x = 1 / 2 or x = -2

State your answer:
x = 1 / 2 and x = -2 are solutions of 2x^2 + 3x - 2 = 0.

Answer 3

a = 2
b = 3
c = -2

quadratic formula is x = [-b + or - sqrt (b^2 - 4ac)]/2a

so we have x = [-3 + sqrt (9 + 16)]/4 = [-3 + 5]/4 = 2/4 = 1/2

or x = [-3 - sqrt (9 + 16)]/4 = [-3 - 5]/4 = -8/4 = -2

so the roots are x = -2 or 1/2

plug in those roots of x and you will see the original equation
yields a true result in both cases

_____________________________________

Also note that given those roots, the factors must be

(x + 2) (x - 1/2)

But since the original equation equals 0, we can mulitply by
a constant and it will still equal 0. So (x + 2) (x - 1/2) = 0 can
rewritten as (x + 2) (2x - 1) = 0 as we simply multiplied both
sides by 2. Using the FOIL method, one can see that
(2x - 1) (x + 2) = 2x^2 + 3x - 2 This too shows the two roots
to be correct.

Answer 4

math problem: 2x^2+3x-2=0


alright x in the question is the variable and the variable always equals 1, so 2x^= 2(1) and 2(1) is 2 times 1 squared ,2^ equals 4

that means 2x^ equals 4

next part after 2x^is 2+3x-2=0 what you do is you leave alone 2+ for a moment and get 3x-2 wich equals 3(1)-2 =1
now add the 2 from before, to 1 which is 3

with the 4 you had in the first step i showed you, add that to 3 which is 7.......if you math problem is a true or false question the answer is false....


if what i said didn't help ask me another math question

Answer 5

Ok.

The solution of a 2nd grade formula is solved from this equation

if
ax^2 + bx + c = 0

-b +- sqrt (b^2 - 4ac)
x = ------------------------------
2a

that tell us that a 2nd grade formula has 2 solution

in our case we have

a = 2 b = 3 c = -2

that mean


-b = -3
b^2 = 9
-4 ac = -4 * 2 * -2 = 16
2a = 4

from that we had

x1 (1st solution) = (-b - sqrt(b^2 - 4ac)) / 2a =
(-3 - sqrt (9 + 16) ) / 4 = (-3 - 5) / 4 = - 8/4 = -2

x2 (2nd solution) = (-3 + sqrt(9+16)) /4 = 1/2

That mean:

2x^2 + 3x - 2 = (x + 2) * (x - 1/2)

Answer 6

2x^2+3x-2=0 (first factor to get rid of exponent)
(2x-1)(x+2)=0 (now we know that one of the values in the parentheses is 0 to make the multiplication problem equal 0

2x-1=0 would make 2x=1 or x=1/2
x+2=0 would make x=-2

so the answer is x= 1/2 or -2

Answer 7

2x^2 + 3x - 2 = 0
Using the quadratic equation,
x = (- 3 ± √(3^2 - 4*2*(-2)))/2
x = (- 3 ± √(9 + 16))/2
x = (- 3 ± √25)/2
x = (- 3 ± 5)/2
x = (- 3 - 5)/2, (- 3 + 5)/2
x = - 8/2, 2/2
x = - 4, 1

Answer 8

[ -B + and - square root(b^2 - 4AC] / 2A

[-3 +- sr(3^2 - 4(2)(-2)] / 2(2)

[-3 +- sr(9 + 16)] / 4

[-3 +- sr(25)] / 4

2 / 4 AND -8 / 4

1/2 and -2

Answer 9

standard form:
0 = ax^2 + bx + c

quadratic formula:
-b +/- sqrt( b^2 - 4ac)
--------------------------
............. 2a


a = 2
b = 3
c = -2

-3 +/- sqrt(3^2 - 4(2)(-2) )
-------------------------------------
.................... 2(2)


-3 +/- sqrt (9 + 16)
-----------------------
............. 4


-3 +/- sqrt(25)
-------------------
........ 4


-3 +/- 5
-----------
..... 4


x = (-3 + 5)/4 = 1/2
x = (-3 - 5)/4 = -2