By property of logarithm in quotient:
Ln(X-1) – Ln(X) = Ln(3)
Ln[(X-1)/X] = Ln(3)
(X-1)/X = 3
X-1 = 3X
-1 = 2X ====> X= -1/2
2007-06-27 19:08:31
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answer #1
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answered by CHARTIGER 2
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Take the e-power of the whole equation. The logarithms disappear, and the subtraction becomes division:
... (x - 1)/x = 3.
Solve this the "normal" way:
... (x - 1)/x = 3.
... x - 1 = 3 x
... -2x = 1
... x = -1/2.
The problem is, however, that you can't take logarithms of negative numbers. Therefore there are no solutions.
You could have seen this immediately from the fact that ln(x-1) is always less than ln(x), so that the left hand side of the equation is negative. However, ln(3) is positive, so there is no solution.
2007-06-28 02:05:45
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answer #2
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answered by dutch_prof 4
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Ln ( x ) - Ln (y) = ln (x/y).........take taht into consideration
so
ln(x-1) - ln(x) = ln( (x-1) / x)
ln (( x-1)/x) = ln 3
take the inverse of ln to both sides which is e^......it cancles out the ln
(x-1)/ x = 3
x-1 = 3x
-1 = 2x
x= -1/2
*********
here is the problem
you can't take the natural log of a number less than 0....
x = -1/2 is less than zero.
Although when you combine the equation as mentioend above...you get a value for x........there is no value for x
no solution
2007-06-28 02:10:43
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answer #3
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answered by My name is not bruce 7
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a property of logarithms is the the difference of two logarithms is the logarithm of the quotient of their contents
so, ln(x-1)-ln(x)=ln[(x-1)/x)]
now, raise e to the power of both sides
the e and the ln cancel each other out
you get:
(x-1)/x=3
x-1=3x
2x=-1
x=-1/2
now you have to check by plugging this in to the original equation
ln(-1/2-1)-ln(-1/2)=? ln(3)
you can't have ln of a negative number so x=-1/2 doesn't work
so, there are no solutions
2007-06-28 02:05:21
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answer #4
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answered by nek0nck2n 2
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No Solution, since a has to be greater than 0 in ln (a)
We know ln (a) - ln (b) = ln (a/b)
so
ln(x-1) -ln (x) = ln 3
ln ((x-1)/x) = ln 3 : raise e both side
(x-1)/x=3
x-1=3x
-1=2x
x=-1/2
since x=-1/2 both ln( x -1 ) and ln (x) will be no solution
2007-06-28 02:18:45
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answer #5
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answered by Mr. Chou 2
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ln(x-1) - ln(x) = ln (3)
=> ln {(x-1)/x} = ln (3)
=> (x-1)/x = 3
=> x-1 = 3x
=> 2x = -1
=> x = (-1/2) or (-0.5)
2007-06-28 02:09:52
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answer #6
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answered by smile 1
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ln(x-1) - ln(x) =ln(3)
ln(x-1)/x) = ln 3
(x-1)/x = 3
x-1 = 3x
-1 = 2x
x = -1/2
No solution possible
2007-06-28 02:10:08
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answer #7
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answered by ironduke8159 7
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ln(x-1)/x = ln(3)...............ln(x) - ln(y) = ln(x/y)
(x-1)/x = 3......................remove ln
x - 1 = 3x
2x = -1
x = -1/2
2007-06-28 02:03:12
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answer #8
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answered by jemai 2
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ln((x-1)/x)=ln3
then you could say
((x-1)/x)=3
then you have
x-1=3x
then2x=-1
and
x=-1/2
2007-06-28 02:02:55
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answer #9
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answered by Nishant P 4
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help meeeeeeeeeeeeeeeeeeeeeeee
2007-06-28 02:13:27
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answer #10
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answered by anu 1
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