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( 2 / (x^2-2x)) - (1/ (x-2))

2007-06-27 15:18:33 · 2 answers · asked by tc 1 in Science & Mathematics Mathematics

2 answers

(2 / (x^2-2x)) - (1/ (x-2))
= 2 / (x(x-2)) - 1 / (x-2)
= 2 / (x(x-2)) - x / (x(x-2))
= (2-x) / (x(x-2))
= -(x-2) / (x(x-2))
= -1 / x, x ≠ 2.

2007-06-27 15:24:59 · answer #1 · answered by Scarlet Manuka 7 · 2 0

( 2 / (x^2-2x)) - (1/ (x-2))

I assume you mean:
2..................1
_____ - ______
x² - 2x.........x - 2


2....................1
______ - ______
x(x - 2).........x - 2


2....................1(x)
______ - ________
x(x - 2).........x(x - 2)


2 - x
_______
x(x - 2)


- (x - 2)
_______
x(x - 2)


-1
___
x

2007-06-27 16:41:16 · answer #2 · answered by jurassicko 4 · 0 0

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