Complex Fraction?

Question

So i get how to do these problems with numbers, but not with letters, so if you can help me i'll be very very thankful...

The directions say to simplify each complex fraction... and th question is

a/b+c divided by a/b-c

any help will be great

Answer 1

[(a/b)+c]/[(a/b)-c] = [(a+cb)/b]/ [(a-cb)/b]

since b is similar to both numerator and denominator, eliminate it....then it becomes

(a+cb)/(a-cb)

Answer 2

The easiest thing to do hear is simplify the top and bottom first.

a/b+c to add find a common denominator in this case b so multiply c by b/b

So a/b +cb/b = (a+cb)/b

It's almost exactly the same on the bottom so for the bottom we get a/b - cb/b = (a-cb )/b

now we have: [ (a+cb)/b ] / [(a-cb )/b]

and when we have a fraction divided by a fraction we multiply by the recipical, so
[ (a+cb)/b ] / [(a-cb )/b] = [ (a+cb)/b ] * [ b / (a - cb) ]

Now we see that the b will cancel so we are left with:
(a+cb)/(a - cb). Which is our answer.

Solution: (a+cb)/(a - cb)

Answer 3

Remember that to divide fractions you must invert the second fraction and multiply.

a/(b+c) * (b-c)/a The a can cancel (be cross-divided).
answer: (b+c)/(b-c) This doesn't simplify any further.

Answer 4

the answer is (a+bc)/(a-bc)